Changes between Initial Version and Version 1 of Ticket #3600, comment 5


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Timestamp:
Feb 17, 2016, 6:35:18 PM (8 years ago)
Author:
Palaxin

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  • Ticket #3600, comment 5

    initial v1  
    44* "smultiply" simplifies the conversion between speed and time: ''new time value = current time value / smultiply''
    55
    6 The question now is where to use which operator. For several technologies affecting the same value "multiply" yields slightly higher values than "bmultiply" since bonuses are included vs. excluded in the calculation. As I stated above I strongly prefer "multiply" instead of "bmultiply" because the descriptions are not correct any more.
     6The question now is where to use which operator. For several technologies affecting the same value "multiply" yields slightly higher values than "bmultiply" since bonuses are included vs. excluded in the calculation. As I stated above I strongly prefer "multiply" instead of "bmultiply" because the %bonus of "bmultiply" actually depends on the bonuses the value already has and is not constant (leading to wrong descriptions).